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1.3v+0.04v^2=200
We move all terms to the left:
1.3v+0.04v^2-(200)=0
a = 0.04; b = 1.3; c = -200;
Δ = b2-4ac
Δ = 1.32-4·0.04·(-200)
Δ = 33.69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.3)-\sqrt{33.69}}{2*0.04}=\frac{-1.3-\sqrt{33.69}}{0.08} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.3)+\sqrt{33.69}}{2*0.04}=\frac{-1.3+\sqrt{33.69}}{0.08} $
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